CPP-EX53

Create a class phone having data members:
1. The STD code    2. The Exchange code      3.    Phone Number
Ex :- 212-766-8901
Write a C++ program to accept details from user (max 10) and change input phone number to new phone number using following criteria:
a)Add 1 to 1st digit of STD code.  (If digit is 9 it becomes 10)
b)    The exchange code is retained as it is.
c)    In 3rd  part of structure, 1st two
digits should be reversed.
Ex: I/P : 212-766-890 => O/P : 312-766-980
Display all changed phone numbers.


#include<iostream.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
class phone
{
    int p,c,s,ph[4],code[3],std[3];
    public:
        void accept();
        void disp();
        void new_ph();
        void convert();
};

void phone::accept()
{
    cout<<"Enter STD no.:\t";
    cin>>s;
    cout<<"Enter Exchange code:\t";
    cin>>c;
    cout<<"Enter phone number:\t";
    cin>>p;
    cout<<"\n\nOld Number:\n";
    cout<<s<<"-"<<c<<"-"<<p;
}

void phone::disp()
{
    cout<<"\n";
    for(int i=2;i>=0;i--)
        cout<<std[i];
    cout<<"-";
    for(i=2;i>=0;i--)
        cout<<code[i];
    cout<<"-";
    for(i=2;i>=0;i--)
        cout<<ph[i];
}

void phone:: convert()
{
    int k=0,i=0;
    while(s>0)
    {
        k=s%10;
        std[i]=k;
        s=s/10;
        i++;
    }
    i=0,k=0;
    while(c>0)
    {
        k=c%10;
        code[i]=k;
        c=c/10;
        i++;
    }
    i=0,k=0;
    while(p>0)
    {
        k=p%10;
        ph[i]=k;
        p=p/10;
        i++;
    }

}
void phone::new_ph()
{
    std[2]=std[2]+1;
    int tmp;
    tmp=ph[1];
    ph[1]=ph[2];
    ph[2]=tmp;
}


int main()
{
    clrscr();
    phone p;
    p.accept();
    p.convert();
    p.new_ph();
    cout<<"\n\nNew Number:";
    p.disp();
    getch();
    return 0;
}